Conditional random events
Task number: 3842
When throwing two different colored six-walled dice of the colors red and blue, consider the following events:
\( A \): 4 fell on the red cube, assuming the sum is 9
\( B \): the sum is 9, assuming that 4 fell on the red cube.
Which of the following cases does hold?
- Both events are equally probable.
- The event \( A \) is more probable than \( B \).
- \( B \) is more probable than \( A \).
Solution
The probabilities are:
\(P(A)=\frac{1/36}{4/36}=\frac{1}{4}\)
\(P(B)=\frac{1/36}{6/36}=\frac{1}{6}\)
Answer
The correct answer is b.
