Consecutive ones

Task number: 3545

Consider a random sequence of one hundred numbers, where each number in the sequence is 0 or 1 and both possibilities occur with probability \(1/2\) independently of the other terms of the sequence. Determine the expected value of the number of occurrences of six consecutive ones. (Optionally generalize for a sequence of \(n\) numbers and consecutive sequences of \(k\) ones.)

  • Solution

    For \(i=1,…,95\) we introduce the event \(A_i\) containing the sequences with ones in positions \(i,i+1,…,i+5\). We have \(P[A_i]=\left(\frac12\right)^6=\frac{1}{64}\).

    Let the random variable \(X\) be the sum of indicator random variables for the events \(A_1,…,A_{95}\).

    By the linearity of expectation we have:

    \(\displaystyle E(X)=E(I_{A_1}+…=I_{A_{95}})=95P(A_1)=\frac{95}{64} \)

  • Answer

    The expected value of the number of occurrences of six consecutive ones is \(\frac{95}{64}\).

    In the general case we obtain the value \(\frac{n-k+1}{2^k}\).

Difficulty level: Easy task (using definitions and simple reasoning)
Solution require uncommon idea
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