Equation with absolute value
Task number: 2763
Solve this equation over the real domain: \(||x-2|-3|=5\).
Resolution
- \(x\le 2: |-x+2-3|=5 \longrightarrow |-x-1|=5 \longrightarrow |-x-1|=5\)
- \(x\le -1: -x-1=5 \longrightarrow x=-6\)
- \(x\ge -1: x+1=5 \longrightarrow x=4\) has no solution
- \(x\ge 2: |x-2-3|=5 \longrightarrow |x-5|=5\)
- \(x\le 5: -x+5=5 \longrightarrow x=0\) has no solution
- \(x\ge -1: x-5=5 \longrightarrow x=10\)
- \(x\le 2: |-x+2-3|=5 \longrightarrow |-x-1|=5 \longrightarrow |-x-1|=5\)
Result
The equation has two solutions: \(x=-6\) and \(x=10\).