Permutation powers

Deretmine powers \(p^{10}\) and \(q^{99}\) for permutations \(p\) a \(q\).

Variant 1
\(p=(6{,}4,1{,}5,3{,}2)\), \(q=(6{,}4,3{,}2,5{,}1)\).
Resolution
Ase \(p^6=\imath\) and \(q^2=\imath\), we get \(p^{10}=p^4=(5{,}1,4{,}6,2{,}3)\), \(q^{99}=q\).
Variant 2
\(p=(1{,}2,7{,}6,5{,}4,3{,}8,9)\), \(q=(1{,}3,5{,}7,9{,}8,6{,}4,2)\).
Result
\(p^{10}=\imath\), \(q^{99}=(1{,}9,2{,}8,3{,}7,4{,}6,5)\).
Variant 3
\(p=(5{,}4,3{,}2,1{,}9,8{,}7,6)\), \(q=(8{,}6,4{,}2,1{,}3,5{,}7,9)\).
Result
\(p^{10}=\imath\), \(q^{99}=(5{,}4,6{,}3,7{,}2,8{,}1,9)\).
Variant 4
\(p=(3{,}6,9{,}2,5{,}8,1{,}4,7)\), \(q=(9{,}8,7{,}6,5{,}4,3{,}2,1)\).
Result
\(p^{10}=q^{99}=q=(9{,}8,7{,}6,5{,}4,3{,}2,1)\).